Question

Among the three positive numbers, the first and second coefficients are 42, second and third are 56 and third and first is 48. So the third is​

Answer 1

Step-by-step explanation:

Let first, second and third numbers be x, y and z, respectively.

Then, xy = 42 ...(i)

yz = 56 ...(ii)

xz = 48 ...(iii)

Multiplying Eqs. (i), (ii) and (iii), we get

(xyz)2=42×56×48

=> (xyz)2=112896

=> xyx=336

Dividing Eq. (iv) by Eq. (i), we get

xyz/xy=336/42

z=8

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Answer 2

Answer:

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