Question

Among the two supplementary angles, the measure of the larger angle is 36° more than the measure

of smaller. Find their measures.(Use Matrix Inversion method). ​

Answer 1

Step-by-step explanation:

let the small angle is x

then larger angle is x+36°

two supplementary angles,so

x+x+36°=180°

2x+36°=180

2x=180-36=144°

x=72°

small angle is 72 degree and large angle is 72°+36°=108°

Answer 2

Answer:

$\huge\color{aqua}\boxed{ANSWER}$

=72

$\huge\color{aqua}\boxed{SOLUTION}$

Let us assume supplementary be x ∘and (180−x) ∘

$\huge\color{aqua}\boxed{Given}$

The measure of the larger angle is 36 ∘

more than the measure of the smaller angle, let the larger angle be x° .

$\huge\color{aqua}\boxed{Then,}$

$(180 - x + 36 = x$

$216 - x = x$

$216 = x + x$

$216 = 2x$

$x = \frac{216}{2}$

$x = 108$

$\huge\color{aqua}\boxed{MEASURE}$

Larger angle =108 ∘

Smaller angle =(108−36) ∘

=72

$\huge\pink{\boxed{\green{\mathbb{\overbrace{\underbrace{\fcolorbox{red}{aqua}{\underline{\pink{ANFELESA\:HERE\:}}}}}}}}}$