Question

Among two supplementary angles the measure of the larger angle is 44°more than the measure of the smaller . Find their measures

Answer 1

Let the angles be x° and x°+44°
Sum of Supplementary angles = 180°
→ x° + x° + 44° = 180
→ 2x° = 180 - 44
2x° = 136°
→ x° = 68°

Angles are 68° and 68° + 44° = 112°

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Answer 2

let larger no. be 'x' n smaller no. be 'y'
according to 1st condition x + y = 180
according to 2nd condition x= 44+y
now substitute x in the 1st equation
44+y+y = 180
44 +2y =180
2y = 180-44
2y=136
y= 136/2
y=68
n x=44+y
x=44+68
x=112
verify
112+68=180
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