Question

among two supplementary angles the measure of the larger angle is 36 degree more than the measure of the smaller angle find the measure of the angles.

in a triangle the sum of angles 2 X + 5 degree and 3 X + 10 degree bracket close is at most 90 degree find the maximum value of the angles​

Answer 1

Answer:

1. Let small angle = x

large angle = x+36

ATQ

x+x+36=180

2x=180-36

x = 144/2 = 72

small angle = x = 72

large angle = x+36 = 72+36 = 108

$2. \: \: 2x + 5 + 3x + 10 = 90 \\ 5x + 15 = 90 \\ 5x = 90 - 15 \\ x = \frac{75}{5} = 15 \\maximum \: angle = \\ 3x + 10 \\ = 3 \times 15 + 10 \\ = 45 + 10 \\ = 55$