Chemistry, asked by avanichatuvedi3926, 11 months ago

Amongst the following hydroxides, the one which has the
lowest value of Kₛₚ at ordinary temperature (about 25ºC) is :
(a) Mg(OH)₂ (b) Ca(OH)₂
(c) Ba(OH)₂ (d) Be(OH)₂

Answers

Answered by Anonymous
0

Explanation:

(d) Be(OH)₂ has the lowest Kₛₚ value.

Answered by brokendreams
1

Be(OH)₂ has the lowest Kₛₚ at room temperature.

Explanation:

  • The Kₛₚ is dependent on the solubility of a compound in water.
  • As the solubility of a substance increase at a particular temperature, the Kₛₚ of that substance increase.
  • The options show us the four hydroxides of group 2 elements.
  • Among a group, we know that the size of the atoms increase while going down the table.
  • So Beryllium have the smallest size among all of them.
  • This results in the tightest bonds with hydroxide radicals because the smaller the central atom, the tighter is the bond.
  • So tighter bond has higher bond energies.
  • So beryllium hydroxide needs highest energy to break Be - OH bonds, hence lowest solubility.

For more information about solubility,

https://brainly.in/question/2934058

What do you mean by solubility? How does the temperature affect the solubility of solid and gas in water.

https://brainly.in/question/4806129

Discuss the solubility of solid liquid and gases in water.explain with suitable example

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