Question

Solubility of BaF₂ in a solution of Ba (NO₃ )₂ will be
represented by
(a) [Ba²⁺ ] (b) [NO₃]⁻²
(c)1/2[F⁻ ] (d) [Ba]²

Answer 1

Solubility of BaF₂ in a solution of Ba (NO₃ )₂ can be represent as

                                                          (c )  $\frac{1}{2} [F^{-} ]$

• here BaF₂ is to be taken as solute and Ba (NO₃ )₂ is to be taken as solvent.
• solubility of a solute in a solvent can be defined as the maximum concentration, when the dissolution process is at equilibrium.                  

                          $BaF_{2}$⇒$[Ba^{2+}]+[{F^{-}]^2$

• Let the solubility of BaF₂ be 's',

                                  $K_{sp}=[Ba^{2+}]{F^{-}]^2$

• The concentration of fluoride ions is given as:

                                            $2s=[F^{-}]\\s=\frac{1}{2} [F^{-}]$

Answer 2

1/2[F⁻ ] Is the correct term.

Explanation:

• Solubility of a particular substance is defined as the amount of solvent getting in 10ml of solute at STP.

• Solubility of different substances varies with Temperature, pressure, presence of other substances in the solution etc.

• In the BaNO3 solution, the barium ions are already present in the solution.

• Now the BaF2 is added in the solution.

• So as the barium ions were already present in the solution, the concentration of barium fluoride cannot be determined by barium ion concentration.

• So concentration of fluoride ions are taken into account.

• Ksp =[Ba2+][F− ]2

• So solubility of the Barium fluoride

• S =1/2[F⁻ ]

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