Question

Amount of heat passing through metallic rod in thermal steady state is Q=kA(T1-T2​)t/L.Obtain the dimension of kwhere A=area of cross section T1 and T2 are temperature L is lengt and t is time.

Answer 1

We know that dimension of heat is same as that of energy- [ML²T⁻²]
And also [t₁]=[t₂]=[K](Kelvin), A=[L²] and t=[T]
Now putting these values in the given equation, we get-
       [ML²T⁻²] ={ k * [L²] * [K] * [T] } / [L]
==> k = [ML²T⁻²] / [L]*[K]*[T]
          =[MLT⁻³K⁻¹]
Hope its helps! :)