Question

amount of ice that can be melted by 4000 calorie of heat latent heat of fusion of ice = 80 g - 1

Answer 1

Latent fusion = 80

Heat=4000

Delta Q= latent fusion×heat

=4000×80

=320000

Hope it helps u

Answer 2

latened ice = 80

melted ice = 4000

= 4000 × 80

= 320000