Question

& A can starts from rest. After 20 seconds, its Velocity becomes 20mls. Find the acceleration and distance covered in 20 seconds.​

Answer 1

Answer:

First we have to find the acceleration of the car.

➠ By the first equation of motion we know that,

v = u + at

➠ Substitute the data,

20 = 0 + a × 20

a = 20/20

a = 1 m/s²

➠ Hence acceleration of the car is 1 m/s²

Distance travelled:

➠ Now we have to find the distance travelled by the car

➠By the third equation of motion,

v² - u² = 2as

➠ Substitute the data,

20² - 0² = 2 × 1 × s

400 = 2s

s = 400/2

s = 200 m

➠ Hence distance covered by the car is 200 m

➠ The three equations of motion are:

v = u + at

s = ut + 1/2 × a × t²

v² - u² = 2as