Question

& A particle of mass 10 g is executing simple harmonic
motion with an amplitude of 0.5 m and periodic time of (π/5)
second. The maximum value of the force acting on
the particle is
(a) 25 N
(b) 5 N
(c) 2.5 N
(d) 0.5 N
​

Answer 1

answer : option (d) 0.5 N

explanation : maximum force , F = $m\omega^2A$

where m is mass of body, $\omega$ is angular frequency and A is amplitude of particle execute simple harmonic motion.

we know, $\omega=\frac{2\pi}{T}$

= 2π/(π/5) = 10 rad/s

amplitude , A = 0.5 m

and mass , m = 10g = 10^-2 Kg

so, maximum force , F = 10^-2 × (10)² × 0.5 N

= 10^-2 × 10^2 × 0.5 N

= 0.5 N

hence, maximum value of force acting on the particle is 0.5 N