Math, asked by karthikpadma2007, 3 months ago

& Find the minimum and maximum values of
( Sin2x-cos2x​

Answers

Answered by rohitsharma9774354
0

Answer:

my dear friend your answer is

Step-by-step explanation:

expression of the form

a sin x +(-) b cos x hes its minimum value as – sqrt(a^2 + b^2) while maximum value sqrt(a^2 + b^2)

hence maximum value of given expression is sqrt(1+1) = sqrt2

Answered by chauhanaaditya43
0

Answer:

thanks thanks thanks thanks thanks thanks thanks thanks

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