Question

& Which one of the following biomolecules is correctly characterized?
[AIPMT MAINS 2012]
a) Palmitic acid - An unsaturated fatty acid with 18 carbon atoms.
6) Adenylic acid - Adenosine with a glucose phosphate molecule.
c) Alanine amino acid - Contains an amino group and an acidic group anywhere in the
molecule.
d) Lecithin - A phosphorylated glyceride found in cell membrane.​

Answer 1

Answer:

Palmitic acid is a saturated fatty acid. It is mainly found in animals, plants, and microorganisms.Its chemical formula is CH

3

(CH

2

)

14

COOH.

Adenosine monophosphate (AMP), also known as 5'-adenylic acid, is a nucleotide. It is used as a monomer in DNA and RNA. It is an ester of phosphoric acid and the nucleoside adenosine. AMP consists of a phosphate group, the sugar ribose, and the nucleobase adenine.

Alanine is an -amino acid with the chemical formula CH

3

CH(NH

2

)COOH. The L-isomer is one of the 20 amino acids encoded by the genetic code. Its codons are GCU, GCC, GCA, and GCG. It is classified as a non-polar amino acid.

Lecithin is the major component of phospholipid portion of cell membrane. Thus, option D is correct and other options are wrong.

So, the correct answer is option D.

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