An 11.0kg object is thrown vertically into the air with an applied force of 145N. What is the initial acceleration of the object?
Answers
Answered by
2
Answer:
a = f / mass
a = 145/11
Explanation:
Answered by
11
Explanation:
F = m ×a,
but also, F = F(applied) + F(gravity)
⇒ m ×a(object) = F(applied) + m× a(gravity)
The acceleration due to the gravity of earth is -9.81 m/s²,
the applied force and the mass of the object are already given, so all that's left is to solve for a.
a(object) = [F(applied) + m × a(gravity)] / m
⇒ (145 N + 11.0kg × -9.81m/s²) / 11.0 kg
⇒ 3.37 m/s²
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