divide Rs 3600 into two parts such that if one part be lent at 9% per annum and the other at 10% per annum the total annual income is $333
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7
Answer:
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=) Let one part be x, then other part is (3600 - x)
Case 1 : SI = (x * 9 * 1) /100
=> SI = 9x/100
Case 2: SI = [(3600-x)*10*1]/100
=> SI = (3600-x)/10
according to problem,
9x/100 + (3600-x)/10 = 333
or, (9x + 36000-10x) = 33300
or, -x + 36000 = 33300
or, x = 36000-33300
or x = 2700
two parts are 2700 and 900
Hope , It Helps ...
Answered by
4
Answer:=) Let one part be x, then other part is (3600 - x)
Case 1 : SI = (x * 9 * 1) /100
=> SI = 9x/100
Case 2: SI = [(3600-x)*10*1]/100
=> SI = (3600-x)/10
according to problem,
9x/100 + (3600-x)/10 = 333
or, (9x + 36000-10x) = 33300
or, -x + 36000 = 33300
or, x = 36000-33300
or x = 2700
two parts are 2700 and 900
Step-by-step explanation:
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