An 18cm long iron pipe has an external diameter 24cm . If the thickness of the pipe is 1cm. Find the total surface area of the pipe.
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Now, Total surface area = Area of both ends +
Curved surface area
Now area of both ends =2(Area of one end)
Now external radius is equal to 24/2=12cm
Now we know thickness of pipe = 1 cm
Therefore internal radius = 11 cm
Therefore area of one end π(12^2-11^2)
=π×12-11×12+11
=23π
Area of both ends =23π×2
=46π
Area of inside curved surface area =2πrh=2π×11×18 = 396π
Area of outer curved surface area=
2π×12×18=432π
therefore total area is equal to 432π+396π+46π=874π = 2746.8 cm^2
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