Question

an+5=35 and an+1=35 find the common difference

Answer 1

$a_{n+1} = a_{n+5}$ = 35

$a + ((n+5)-1)d = a + ((n+1)-1)d\\(n+4) d = nd\\(n+4)d - nd = 0\\(n+4-n)d = 0\\4d = 0\\d =0$

Clearly we can see that the terms are equal which is only possible when d is 0 in an ap.

Therefore, the AP will be 35,35,35, so on.

(mark as brainliest as it took time to write with math input :D)