Computer Science, asked by tomba1194, 10 months ago

An 8-bit computer has a 16-bit address bus.The first 15 lines of the address are used toselect a bank of 32k bytes of memory. Thehigh-order bit of the address is used to select aregister which receives the contents of thedata bus. Explain how this configuration canbe used to extend the memory capacity of thesystem to eight banks of 32k bytes each, for atotal of 256k bytes of memory

Answers

Answered by indiabrainly
9

Answer:

Explanation:

When it comes to the processor we get to see that it generally makes a seletcion of the external register that has an address of 8000 units or hexadecimal. Each of the separate bank then comes with a 32K byte which has a definite address of 0000-7 FFF.

Therefore, we get to see that the processor loads an extra 8-bit number inside the register which has seven number of 0s along with a single 1.

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