An 8 N force acts on a rectilinear conductors of 20 cm long placed perpendicular to magnetic field.
Determine the magnetic field induction if the current in the conductor is 40 A.
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Answer:
Explanation:
Given force, F=8N
Length of conductor l=20cm=0.2m
Current in conductor, I=40A
Now, magnetic field B=?
Using F=BIl
⟹B=
Il
F
=
0.2×40
8
=1T
⟹
B
=1 Tesla
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