an 8000kg engine pulls a train of 5 wagons each of 2000 kg if the engine exerts a force of 40000n and the track offers friction of 5000n then calculate the force of wagon 1 on wagon 2
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Hello mate!!!
Here's ur answer
Given:-
The force of wagon 1 on wagon 2 = mass of four wagons x acceleration
⇒F=4×2000 kg×1.944ms−2⇒F=4×2000 kg×1.944ms-2
⇒F=8000 kg×1.944ms−2⇒F=8000 kg×1.944ms-2
⇒F=1552N⇒F=1552N
The force of wagon 1 on 2 = 1552 N
Hope it helps you
Here's ur answer
Given:-
The force of wagon 1 on wagon 2 = mass of four wagons x acceleration
⇒F=4×2000 kg×1.944ms−2⇒F=4×2000 kg×1.944ms-2
⇒F=8000 kg×1.944ms−2⇒F=8000 kg×1.944ms-2
⇒F=1552N⇒F=1552N
The force of wagon 1 on 2 = 1552 N
Hope it helps you
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