Question

An elevator descends into a mine shaft at the rate of 6 m/min . if the descent start from 10 m above the ground level, how long will it take to reach -35 m. ​

Answer 1

CORRECT QUESTION⬇️

$\leadsto$Q)An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above ground level, how long will it take to reach −350 m.

$\huge\underline\mathbb\red{GIVEN}$

Distance descended is denoted by a negative integer,

Initial height =+10 m

Final Depth =−350 m

$\huge\underline\mathbb\purple{now}$

Given, the time is taken by the elevator to descend −6 m=1 minute.

Thus, time taken by the elevator to descend.

$- 360m = \frac{ - 360}{ - 6}. \\ \\ formula \: used. \\ \\\mapsto speed \: = \frac{distance}{time}. \\ \\ ✅60min$

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