An a
aqueous solution
solution of urea Coils
above
160°C but freezed below 0°C.
Explain ?
Answers
Answered by
0
Answer:
hi am kiran shinde u are tok mi
Answered by
1
Answer:
K
f
=1.86 Kkg/mol;K
b
=0.512 Kkg/mol;T
f,solution
=−0.186
o
C and T
f,water
=0
o
C
ΔT
f
=0.186 K
Since,
K
f
ΔT
f
=
K
b
ΔT
b
=m
ΔT
b
=
1.86
0.186
×0.512=0.0512 K
As, T
b,water
= 373K, and
ΔT
b
=0.0512 K
Since there is an elevation in boiling point upon addition of solute
∴ T
b,solution
=373+0.0512 = 373.0512 K
Similar questions