An a bus starting from rest moves with a uniform acceleration of 0.4m/s square for 8 minutes .find 1 = speed acquired 2 =distance travelled
Answers
Answered by
0
u=0
a=0.4m/s2
t=8mins=480s
v=u+at
v=0.4*480
v=192m/s
2as=v2-u2
0.8s=36864
s=36864/0.8
s=46080m
a=0.4m/s2
t=8mins=480s
v=u+at
v=0.4*480
v=192m/s
2as=v2-u2
0.8s=36864
s=36864/0.8
s=46080m
Answered by
0
convert time in seconds and then go ahead
for first part use
v = u + a.t
and for second part
s = u.t + (1/2)a.t.t
or v.v = u.u + 2.a.s
where u is initial velocity and
v is final velocity and
s is distance.
Hope it helped more.
for first part use
v = u + a.t
and for second part
s = u.t + (1/2)a.t.t
or v.v = u.u + 2.a.s
where u is initial velocity and
v is final velocity and
s is distance.
Hope it helped more.
Attachments:
Similar questions