Question

an A.P consists of 50terms of which 3rd term is 12 and last term is 106.find the 29th term of AP

Answer 1

a+2d = 12 equation 1st

a+49d = 106 equation 2nd

solved by elimination method

subtracting equation 2 from 1st

a+2d=12

-a-49d=-106

___________________

-47d=-94

d= -94/-49

d=2

put the value of d in equation 1st

a+2d=12

a+2× 2=12

a=12-4

a=8

for find the 29th term

t29=a+(n-1)×d

=8+(29-1)×2

=8+28×2

=8+56

=64 ans.

Hope! it will be helpful for you