Question

An A.P. consists of three terms whose sum is 15 and sum of their squares of extremes is 58. Find the first three terms of A.P. And also find the sum of first 50 terms of an AP​

Answer 1

hope this answer will be helpful

Answer 2

Answer:

3,5,7&,2575

Step-by-step explanation:

(a-d)+a+(a+d)=15

3a=15

a=5

(a-d)2+(a+d)2=58

(a minus d ka whole square + a plus d k

a whole square)

(5-d)2+(5-d)=58(5 minus d ka whole square + 5 plus d ka whole square )

25+d2+10d +25+d2 - 10d=58

2d2=58-50

2d2=8

d2 = 4

d=2

a-d=5-2=3,a=5,a+d=5+2=7

a50 =a+(50-1)d

a50 =5+49*2=103

sn =n/2(a+l)

a50=