an a.p has the first term as 2 and the common difference as 4 . which term in the a.p is the first multiple of 23 to appear in the a.p?
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Given , first term is a =2
common differance is d=4
then the a th = 48
46= 2+ (n-1)d46
= 2+ 4n - 446
= 4n-24n
= 48 n
= 48/4
=12
Hence 12th term is the first multiple of 23
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