Science, asked by manthanugale, 1 month ago

An a-particle and a proton is projected towards the same nucleus, in different experiments.

The ratio of their distances of closest approach is :

(A) 2 : 1, if their initial kinetic energy was same

(B) 8 : 1, if their initial momentum was same

(C) 1 : 2, if their initial speed was same

(D) 1 : 1, if their initial kinetic energy was same​

Answers

Answered by lyamuna14
0

Answer:

m

=4 amu mp=1 amu

K.ϵ

K.ϵ

.

=

1/2m

p

V

p

2

1/2m

V

2

=1

⇒4v

2

=Vp

2

⇒Vp=2V

we know that,

V

2

=u

2

+2aS

V

p

2

−up

2

=2aSp

V

2

−u

2

=2aS

Initial velocities up=u

=0

u

V

2

V

p

2

=

S

S

P

⇒Sp:S

=4:1

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