Question

An ac circuit consists of a resistor of 5 ohm and an inductor of 10 mH connected in series with a 50 V /50 Hz supply. What capacitance should be connected in series with the circuit to obtain maximum current? What will be the maximum current?​

Answer 1

Answer:

Correct Answer - A f = 1 2 π √ L C f=12πLC f 2 = 1 4 π 2 L C f2=14π2LC C = 1 4 π 2 L f 2 C=14π2Lf2 = 1 4 × 9.87 × 10 × 10 − 3 × 2500 =14×9.87×10×10-3×2500 = 1 × 10 − 3 F =1×10-3F =1mFRead more on Sarthaks.com - https://www.sarthaks.com/1973730/circuit-consists-resistor-5omega-inductor-connected-series-supply-capacitance-should

Explanation:

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