Question

An AC source is 120v 60Hz. The value of voltage after
1/720 s from start will be

Answer 1

V=V°sin wt
V=Vrms√2sin wt
t=1/720s
V=120√2sin2πvt
120√2sin2π*60*1/720
60√2=84.8v

Answer 2

Dear Student,

● Answer -

V = 84.85 V

◆ Explanation -

# Given -

Vrms = 120 V

f = 60 Hz

t = 1/720 s

# Solution -

Value of voltage after 1/720 s is -

V = Vo.sin(wt)

V = √2.Vrms × sin(2π×60×1/720)

V = √2 × 120 × sin(π/6)

V = √2 × 120 × 0.5

V = 84.85 V

Hence, the value of voltage after1/720 s from start will be 84.85 V.

Thanks dear. Hope this helps you...