Question

an ac source of 200v 50hz is connected in series with 3 ohm resistors ,790uF capacitor and 25mH inductor in series.Find impedance and current through the circuit​

Answer 1

Answer:

please mark me brainalist

Explanation:

Here V

rms

=200V,X

L

=50Ω,X

C

=50Ω,R=25Ω

Impedance of the circuit,

Z=

R

2

+(X

L

−X

C

)

2

=

25

2

+(50−50)

2

=25Ω

Current in the circuit , I

rms

=

Z

V

rms

=

25Ω

200V

=8A

Voltage drop across the inductor is

V

L

=I

rms

X

L

=8A×50Ω=400V