Question

An AC source of emf 5.0 V is connected to a series RLC circuit at a phase angle of 33°,
Find the potential difference across the capacitor when the magnitude of potential
difference across the inductor reaches the maximum value of 6.0 V.
(a) 6.9 V
(b) 2.9 V
(c) 12.8 V
(d) 3.3 V
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ОА
OB
OD
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Answer 1

Answer:

ANSWER

Given,

VR=40V

VL=60V

VC=30V

From the vector diagram,

V=VR+j(VL−VC)

V=40+j(60−30)

 

V=40+30j

Magnitude,

V=(40)2+(30)2=2500V

V=50V

The correct option is B.