Question

An advertisement board is in the form of an isosceles triangle with perimeter 36
and each of the equal sides are 13 m. Find the cost of painting it at 17.50 per
square metre.

Answer 1

please see the attachment

Answer 2

Cost of painting it at 17.50 per  square metre is Rs 1050

Solution:

Given that,

An advertisement board is in the form of an isosceles triangle with perimeter 36  and each of the equal sides are 13 m

Let "a" , "b", "c" be the sides of triangle

Given is a isosceles triangle, each of the equal sides are 13 m

Therefore,

a = b = 13

Given that perimeter is 36 m

We know that,

perimeter = a + b + c

36 = 13 + 13 + c

36 = 26 + c

c = 36 - 26

c = 10

Find the area of triangle

The area of triangle is given as:

$Area = \sqrt{s(s-a)(s-b)(s-c)}$

Where, s is half of perimeter

s = 36/2 = 18

Therefore,

$Area = \sqrt{18(18-13)(18-13)(18-10)}\\\\Area = \sqrt{18 \times 5 \times 5 \times 8}\\\\Area = \sqrt{3600}\\\\Area = 60$

Find the cost of painting it at 17.50 per square metre

Cost = 60 x 17.50

Cost = 1050

Thus cost of painting it at 17.50 per  square metre is Rs 1050

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