Question

An advertisement claims that a certain 1200-kg car can accelerate from rest to a speed of 25 m/s in a time of 8 s. What average power must the motor produce to cause this acceleration? Ignore friction losses.

Answer 1

Answer:

The work done in accelerating the car is given by

W=ΔK= 21

m(v f2−vi2)= 21

[1200(25) 2 −0]=375kJ

Power = t/W = 8/375

=46.9kW

Explanation:

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