an aeroplane at an altitude of 250m observes the angle of depression of two boats on opposite banks of a river to be 45 and 60 degrees respectively. find the width of the river . write the answer correct to nearest whole number
Answers
Answered by
51
From the figure attached
B1 = Boat 1
B2 = Boat 2
tan 60 = OB2/250
OB2 = 250 tan 60 = 250 x 1.732 = 433 m
tan 45 = OB1/250
OB1 = 250 tan 45 = 250 x 1 = 250
Width of the river = OB2 - OB1
= 433 - 250
= 183m
B1 = Boat 1
B2 = Boat 2
tan 60 = OB2/250
OB2 = 250 tan 60 = 250 x 1.732 = 433 m
tan 45 = OB1/250
OB1 = 250 tan 45 = 250 x 1 = 250
Width of the river = OB2 - OB1
= 433 - 250
= 183m
Attachments:
reetagurung392:
This answer is wrong .
Answered by
2
Answer:
393
Step-by-step explanation:
tan 45=h/b
1=h/b
1=25
b
b=250
tan 0=h/b
√3=50/b
b=20/√3
eq 1 & 2
250+250/√3
250+250/√3×√3
/√3
250+83×√3
250+83×1.732
50+143.7
393.7
I Hope it will help u
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