An aeroplane at an altitude of 900 m. finds that two ships are sailing towards it in the same direction. The angles of depression of the ships, as observed from the plane are 60 degree and 30 degree respectively. Find the distance between the ships.
Answers
Answer:
A) medicine /(B) trained /(C) type of /(D) the doctor is /(E) in this5010A parallel plate air capacitor is charged to 50 V and is then connected to an uncharged geometrically identical capacitor in parallel. The second capacitor has some dielectric medium between its plates. If the common potential is 10 V,
Answer:
600sqrt(3)m
Step-by-step explanation:
Based upon the given information, we can draw the above shown diagram.
Here,
∠OBP=30
∘
,∠OAP=60
∘
,OP=900 m
To find: AB
Solution:
We know that, tanθ=
B
P
∴ In △OPB,
tan30
∘
=
PB
900 m
⇒
3
1
=
PB
900
⇒PB=900×
3
m
∴ PB=900
3
m
Now, in △OAB,
tan60
∘
=
PA
900 m
⇒
3
=
PA
900
⇒PA=
3
900
m=
3
900
3
m
∴ PA=300
3
m
AB=PB−PA=900
3
−300
3
=600
3
m
∴AB=600
3
m
Hence, the distance between the two ships is 600
3
m.