Question

An aeroplane covers 2500 km, 1200 km and 500 km at the rate of 500 km/hr, 400 km/h
250 km/hr respectively. Find its average speed for the whole journey.
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Answer 1

Answer:

first lets find the total hours of the journey

time = distance / speed

2500/500 = 5 , 1200/400 = 3 , 500/250 = 2

total time was 5 + 3 +2 = 10 hours,

now calculate total distance --> 2500 + 1200 + 500 = 4200

average speed = distance / time

= 4200/10

= 420 km/hr

Step-by-step explanation:

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Answer 2

Answer:

Answer:

${\large{\boxed{\colorbox{lime}{\pink{\text{QUESTION}}}}}}$

an Aeroplane covers 2500km, 1200km,and 500km at the rate of 500 km/hr, 400km/hr and 250km/hr respectively. find its average speed.

${\large{\boxed{\colorbox{lime}{\pink{\text{answer}}}}}}$

$\sf{\bold{\red{ distance=500km}}}$

speed=500km/hr

$\sf{\bold{\blue{time \: taken \: to \: cover \: 2500 \: km:}}}$

$\frac{2500}{500} = 5hrs$

$\sf{\bold{\green{distance=1200km}}}$

$\sf{\bold{time: 400km/hr}}$

$\sf{\bold{\red{ time \: taken = }}}$

$\frac{1200}{400} = 3hr$

$\sf{\bold{\orange{distance=500}}}$

$\sf{\bold{\blue{speed=250km/hr}}}$

$\sf{\bold{\green{time \: taken=}}}$

$\frac{500}{250}= 2hr$

$\sf{\bold{\red{total \: distance = }}}$

$2500 + 1200 + 500 = \: 4200km$

$\sf{\bold{\orange{total \: time \: taken = }}}$

$5 + 3 + 2 = 10$

$\sf{\bold{\blue{average \: speed=}}}$

$\sf{\bold{\green{ \frac{4200}{10} = }}}$

${\large{\boxed{\colorbox{lime}{\pink{\text{420km/hr}}}}}}$