Question

An aeroplane delayed by half an hour if it travels at a speed of 250 kmph more speed than previous to reach destination at the same time then find the original speed.

Answer 1

➡️Solution:

Let the original speed of Aeroplane is 'x' kmph
and it travels in 't' hours

As we know that

Speed = Distance/time

If speed is 250 kmph more,ie x'= (x +250) kmph

Time taken =0.5 hour less => t' =(t-0.5) hours

Since distance of journey is same in both the cases,it is not given in the problem.

$xt = (x + 250)(t - 0.5) \\ \\ xt = xt - 0.5x + 250t - 125 \\ \\ 0.5x = 250t - 125 \\ \\ x = 500t - 250 \\ \\ \\ x = 250(2t - 1) \: kmph$


If distance of journey is given than time taken can be calculated by speed,distance and time formula.

Hope it helps you.