An aeroplane flies due east along the equator with a speed of 300m/s. determine the magnitude and direction of the coriolis acceleration.
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Coriolis acceleration is the acceleration of a moving body in a rotating frame of reference. It is a fictitious force. We are referring to the rotation of EArth about itself.
Angular velocity of Earth = ω = 2π /86400 rad/sec
direction from South to North
Velocity of the Aeroplane = v = 300 m/s East
Coriolis acceleration = - 2 * ω X v
(vector product of ω for the frame and v)
= - 2 * 2π / 86400 rad/sec * 300 m/s
= - 0.0436 m/sec²
The direction is along the radius of Earth at the location of Aeroplane and pointing out of Earth's surface.
Angular velocity of Earth = ω = 2π /86400 rad/sec
direction from South to North
Velocity of the Aeroplane = v = 300 m/s East
Coriolis acceleration = - 2 * ω X v
(vector product of ω for the frame and v)
= - 2 * 2π / 86400 rad/sec * 300 m/s
= - 0.0436 m/sec²
The direction is along the radius of Earth at the location of Aeroplane and pointing out of Earth's surface.
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