Question

An aeroplane flying at a height of 300 metres above the ground passes vertically above another plane at an instant when the angles of elevation of the two planes from the same point on the ground are 60 and 45, respectively. Then the height of the lower plane from the ground, in metres, is

Answer 1

Answer:

100√3 = 173.2 approx

Step-by-step explanation:

Distance of Higher plane from view point will be

d * sin60° = 300

d = 300 * 2/(√3)

Now D cos 60° = Base (B)

So, B = 100√3 = Required height

Since, tan 45° = Required height/Base