Question

an aeroplane flying at a height of 3000m and after 2 second it move from position A to B if the angel of elevation to point A is 60 degrees & to point B is 45 degrees from ground
. find the speed of plane?

Answer 1

ht of the plane from ground = 3000m

Time taken= 2sec

tan 60 = opp side/adj side

√3= 3000/adj side

adj side= 3000/√3

adj side= 1000√3m

For position B

tan 45= opp side/adj side

1 =3000/adj side

adj side= 3000m

therefore total distance traveled =1000(3-√3)

there fore speed =total distance traveled/time taken

speed= 1000(3-√3)/2

speed=500(3-√3)km/hr

Answer 2

hey mate ,here's your answer
hope it helps you