Question

An aeroplane flying horizontally at a height of 1.96 km with a velocity of 300 ms-1 drops a bomb when
it is exactly above a point A on the ground. The bomb strikes a target at a point B on the ground. Then
distance between A and B is
[b ]
a) 3 km
b) 6 km
c) 9 km
d)12 km​

Answer 1

Answer:

First we find how much time bomb will take to reach the ground ,

That will be

$t = \sqrt{ \frac{2h}{g} } = \sqrt{ \frac{2 \times1.96 \times 1000m }{9.8} } = 20 \: s$

Now bomb has a velocity of 300m/s in horizontal

So distance it travelled will be

$= 300 \times 20 \: m \\ = 6 \: km$

Answer 2

Answer:

h=1.96×103 m

u=300 m/s

g=9.8 m/s

R=u2hg−−√

R=6 km