Question

An aeroplane had altitude of 1200m in find that 2 ship are sailing towards it in the same direction the angle of depression of two ships as abserved from aeroplane are 60° and 30° find the distance

Answer 1

The height of the aeroplane can be AB

and C and D be the position of 2 ships.

Let ∠ ABC = 60° and ∠ADB = 30°

Let BC = xm, CD = y m

in triangle ABC,

tan 60° = AB/BC

√3 = 1200/x

x = 1200/√3 = √3/√3

= 400√3 m

In triangle ABD

tan 30° = AB/BD

= 1/√3 = 1200/ x + y

y = 1200/√3 - 400√3 = 800√3

The final answer for this question is 800√3

If there is any confusion please leave a comment below.

Answer 2

tan60=1200/x.   root3=1200/x.     x-1200/root3=400root3.     tAn30 =.1200/x+x=1/root3. 1200root3 =x+y       1200root3-400root3=y.then y is 800root3 that is 1385.6