Question

An aeroplane has 4 seats for passengers. Those willing to pay first class fares can take 60 kg of baggage each, but tourist class passengers are restricted to 20kg each. The plane can carry only 120 kg of baggage altogether . To find the number of passengers of each kind use cramer's rule

Matrix question​

Answer 1

Given : An aeroplane has 4 seats for passengers.

first class fares can take 60 kg of baggage each

tourist class passengers are restricted to 20kg each.

The plane can carry only 120 kg of baggage altogether

To Find :  the number of passengers of each kind

use cramer's rule

Solution:

first class fares Passenger = x

tourist class passengers = y

x + y  = 4

60x + 20y  = 120

=> 3x  + y  +  6

x + y  = 4

3x  + y  +  6

$\left|\begin{array}{ccc}1&1 \\3&1\end{array}\right| = 1 \times 1 - 3 \times 1 = - 2$

$x = \frac{\left|\begin{array}{ccc}4&1 \\6&1\end{array}\right|}{\left|\begin{array}{ccc}1&1 \\3&1\end{array}\right|}$

=> x =  (4 - 6)/-2

=> x = 1

$y = \frac{\left|\begin{array}{ccc}1&4 \\3&6\end{array}\right|}{\left|\begin{array}{ccc}1&1 \\3&1\end{array}\right|}$

=> y = (6 - 12)/-2

=>y = 3

number of passengers in first class = 1

number of passengers in tourist class = 3

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Answer 2

Step-by-step explanation:

✰ Question ⤵

An aeroplane has 4 seats for passengers. Those willing to pay first class fares can take 60 kg of baggage each, but tourist class passengers are restricted to 20kg each. The plane can carry only 120 kg of baggage altogether . To find the number of passengers of each kind use cramer's rule

✰ Given ⤵

An aeroplane has 4 seats for passengers.

first class fares can take 60 kg of baggage each

tourist class passengers are restricted to 20kg each.

The plane can carry only 120 kg of baggage altogether

✰ To Find ⤵

The number of passengers of each kind

use cramer's rule

✰ Solution ⤵

An aeroplane has 4 seats for passengers.

first class fares can take 60 kg of baggage each

tourist class passengers are restricted to 20kg each.

The plane can carry only 120 kg of baggage altogether

To Find : the number of passengers of each kind

use cramer's rule

Solution:

first class fares Passenger = x

tourist class passengers = y

x + y = 4

60x + 20y = 120

=> 3x + y + 6

x + y = 4

3x + y + 6

$\begin{gathered}\left|\begin{array}{ccc}1&1 \\3&1\end{array}\right| = 1 \times 1 - 3 \times 1 = - 2\end{gathered}$

$\begin{gathered}x = \frac{\left|\begin{array}{ccc}4&1 \\6&1\end{array}\right|}{\left|\begin{array}{ccc}1&1 \\3&1\end{array}\right|}\end{gathered}$

=> x = (4 - 6)/-2

=> x = 1

$\begin{gathered}x = \frac{\left|\begin{array}{ccc}1&3 \\3&6\end{array}\right|}{\left|\begin{array}{ccc}1&1 \\3&1\end{array}\right|}\end{gathered}$

=> y = (6 - 12)/-2

=> y = 3

• Number of passengers in first class = 1

• Number of passengers in tourist class = 3

Hope it helpful.. ✨️

@Somya2563