Question

An aeroplane has a run of 500m to take off from the runway.it starts from rest and moves with constant acceleration to cover the runway in 30 sec.what is the velocity of the aeroplane at the take off?

Answer 1

Answer:

v=100/3 m/s or 33.33 m/s. (v is velocity of the aeroplane to take off).

Explanation:

s=ut + 1/2at2

500=0×t + 1/2a(30×30)

500=1/2a(900)

500=450a

50/45= a

10/9 m/s2 = a.

velocity of the aeroplane to take off=?.

by using v=u + at

v=0 +(10/9)(30)

v=100/3 m/s. or 33.33 m/s.

hope it helps...