Question

An aeroplane is flying at 1960 m with velocity of 600 km/hr. A bomb is dropped at some point a while it reaches at b. The distance between a and b is.?

Explain in detail plz

Answer 1

hey buddy here is your answer by UDIT

distance between A and B is same as the RANGE of a projecticle launched horizontally from some HEIGHT

so RANGE = Ux × time

here time =
$\sqrt{2h \div g}$
HEIGHT =1960 m

so time =

$\sqrt{2 \times 1960 \div 9.8}$
=20 second

and Ux= 600km/hr (since initial velocity of bomb = velocity of plane )
and 600km/hr= 166.66 m/s

so

range = 166.66×20 = 3333.33 m

thanks