An aeroplane is flying at the height of 300 m above the ground. Flying at this height, the angles of depression of 2 points from the aeroplane on the both banks of the river in opp. direction are 45 and 60. Find the width of the river.
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Answer: tan 45° = 300/y
1 = 300/y
y = 300
tan 60° = 300/x
√3 = 300/x
x = 300/√3
x = 100√3
Width of river = x + y
= 300 + 100√3
= 300 + 173.2
= 473.2 m
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