Question

An aeroplane is flying horizontally from west to east with a velocity of 900 km/hr calculate the potential difference developed between the ends of its wings having a span of 20 m the horizontal component of the earths magnetic field is 5×10⁻⁴T and the angle of dip is 30°

Answer 1

Potential difference developed between the ends of the wings 'e' = BlvsinФ

v= 900 km/hr =250 m/s

b=5* $10^{-4}$ T

l=20m

Ф= 30°

∴ e = 5*10$10^{-4}$ * 20 * 250 * sin 30°

     = 1.25

Answer 2

Answer:

Explanation:

Here you go