Question

An aeroplane is flying horizontally from west to east with a velocity of 900 km/hr calculate the potential difference developed between the ends of its wings having a span of 20 m the horizontal component of the earths magnetic field is 5×10⁻⁴T and the angle of dip is 30°

Answer 1

I think this question is from CBSE 2018 physics Paper.
Potential developed= BVL sin30
V=900km/hr = 250m/s
B= 5×10^(-4) Tesla
L= 30m
Put the value and get the answer.

Answer 2

This Question is from CBSE 12 Physics Board Examinations and is a simple problem of just using a simple equation ,

Velocity(V) =250m/s

Length of conductor(wing)(L)=20m

Magnetic Field(B)=5 x 10^-4 T

Bv(Magnetic Field's Vertical component)=sin 30=1/2

Therefore

ε=BLVsinΘ

=5x10^-4 x 20 x 250 x 1/2

=1.25V