Question

An aeroplane is flying horizontally with a velocity
of 600 km/h and is at a height of 1960 m. When it
is vertically at a point A on the ground, a bomb is
released from it. The bomb strikes the ground at
point B. The distance AB is -
1) 33km 2) 1200m 3) 3.33km 4) 0.33km




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Answer 1

Explanation:

The velocity with which the bomb is released is 600km/h(horizontal).

Vertical velocity of the bomb is zero.

So.distance AB=600

18

5

∗t t is the time taken by the bomb to reach the ground.

1960=g

2

t

2

which gives AB equal to 3.3.km.

Answer 2

Answer:

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Explanation:

see in the question its given:

Velocity= 600Km/hr = 600x1000/3600 m/s=166.66m/s

Ht=1960m.

To Find: The range of the projectile (R).

Its actually a Projetile motion .

For a projectile Ht=1/2*g*t*t.There fore we get t= 20s.

R=V*t=166.66*20=3333.33m/s=3.333Km/hr.