Question

An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m.At what angle of sight should it release a bomb if it is to strike the target on the ground?

Answer 1

I didn't got your question

Answer 2

Given :-

A aeroplane is flying at the height of 1960 m at a speed of 600 Km/h.

So time taken,

t = √2h/g

t = √2×1960/9.8

t = √400

t = 20 s

u = 600 × 5/18 = 500/3 m/s

x = ut

x = 500/3 × 20 = 10000/3

x = 10000/3 m

tanØ = x/y

tanØ = 10000/3 × 1960

tanØ = 10/5.88

tanØ = 1.73

tanØ = √3

Ø = 60°

Hence,

The angle of sight = Ø = 60°