An aeroplane lands at a speed of 432 km/hr and stops after covering a runaway of 4 km. Calculate (i) acceleration (ii) time in which it comes to rest.
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Given that
Landing speed=432km/h
Covering=4km
Therefore acceleration =v-u÷time
=432-0÷3600sec
=0.12m/sec
Landing speed=432km/h
Covering=4km
Therefore acceleration =v-u÷time
=432-0÷3600sec
=0.12m/sec
adisingh0440:
i not study
not in syllabus
but i need
ok
acceleration is right?
its not accelearation its retardation
retardation = -0.12m/sec^2
could u pls help me
who me
yes u
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